14-x>0?????
-x>-14 multiply by -1 and change > into < x<14
do you get it?
so its not 14<x?
14-x>0 add -14 to both sides... equation becomes... 14-14-x>-14 0-x>-14 -x>-14 multiply by -1 and change > into < x<14
no it is not 14<x because... EXAMPLE let's say x=15 so that would be 14<x because 14<15 right?? now we have... 14-15>0 -1>0 ---> And this is wrong ! That's why x<14 is correct :D
bless you my good man/woman.
man hahaha.. :P you too my friend , Glad to help ;)
ida just added x to each side
but then won't you have to swap the inequality?
why not?
the only need to swap an inequality is if you multiply or divide by a negative; i try to avoid that in general
14-x > 0 +x +x --------- 14 > x
does swap means ... never mind, I thought something else, (since I'm not British/American .. I don't understand some words) swap= change right??
you mentioned avoiding swapping the inequality signs, now? using the same method you posted
yes@kreshink to swap is to change
@st like @ami said ... you change\swap the sign ONLY when you multiply by negative number ! otherwise you don't have to.... (you shouldn't )
in the end, the math works the same as long as you apply it correctly :)
but @amistre64 said he/she tries to avoid to swapping, i took that to mean, theres another ways of solving compound inequalities that involve division or multiplication with swapping signs
in general, you always "turn the equality" sign around when you multiply or divide by a negative number to keep everything in order. They dont teach you this when using the "=" sign since it rather pointless to turn it around.
\[-7 < 3\] \[-7(-1) < 3(-1)\] \[7< -3;\ \text{ unless we flip the sign this statement is false}\] \[7> -3;\ \text{ now its true}\]
yes
if we simply go about it with addition and subtraction we get: -7 < 3 +7 +7 ------- 0 < 7+3 -3 -3 -------- -3 < 7 ; no need to flip a sign when adding and subtracting is involved
sick
14-x\[14->0\] -x\[-x >14\] \[x/->14/-\] \[x <14\]
Join our real-time social learning platform and learn together with your friends!