A ladder of length L = 2.8 m and mass m = 19 kg rests on a floor with coefficient of static friction μs = 0.48. Assume the wall is frictionless.
1)What is the normal force the floor exerts on the ladder?
2)What is the minimum angle the ladder must make with the floor to not slip?
A ladder of length L = 2.8 m and mass m = 19 kg rests on a floor with coefficient of static friction μs = 0.48. Assume the wall is frictionless.
1)What is the normal force the floor exerts on the ladder?
2)What is the minimum angle the ladder must make with the floor to not slip?
@Mathematics

Question

A ladder of length L = 2.8 m and mass m = 19 kg rests on a floor with coefficient of static friction μs = 0.48. Assume the wall is frictionless.
1)What is the normal force the floor exerts on the ladder? 
2)What is the minimum angle the ladder must make with the floor to not slip?  
A ladder of length L = 2.8 m and mass m = 19 kg rests on a floor with coefficient of static friction μs = 0.48. Assume the wall is frictionless.
1)What is the normal force the floor exerts on the ladder? 
2)What is the minimum angle the ladder must make with the floor to not slip?  
@Mathematics

anonymous · Answer

are the answers 95N and 76.5 degree?

anonymous · Answer

I am not sure. Want some advice. Could someone give their helping hand,please?

anonymous · Answer

It's lengthy to explain, so I'm keep thinking to go shortcut :(
However the angle is = arctan ( 1/.98) = 45.58 degree.