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hmm there might be an easier way but i would solve for y making sure you use the result that includes -12, -5. then I would take a derivative with respect to y. this gives you the slope at any x. plug in your x to get slope. Now you have slope and a point so we can write down an equation for the line
by differentiating 169=x^2+y^2, you can get the slope of the line 0=2x+2y(dy/dx) (dy/dx)= -2x / 2y = -x/y put x=-12 and y=-5 dy/dx = 12/-5 = -12/5 the required equation: y-(-5) = (-12/5)(x+12) y =(-12/5)x -169/5
*with respect to x
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