Find the horizontal limit(s) of the following function:
f(x) = \frac {11 x^3 - 9 x^2 -10 x }{ 9 - 11 x - 10 x^3 }
?and ?

Question

Find the horizontal limit(s) of the following function:
f(x) = \frac {11 x^3 - 9 x^2 -10 x }{ 9 - 11 x - 10 x^3 }
?and ?

anonymous · Answer

(-11x^3+9x^2+10x)

anonymous · Answer

how so i solve it?

shayaan_mustafa · Answer

kindly make standard form of your question. so I could understand.

shayaan_mustafa · Answer

@rukh

anonymous · Answer

Find the horizontal limit(s) of the following function:
f(x) = \frac {11 x^3 - 9 x^2 -10 x }{ 9 - 11 x - 10 x^3 }

shayaan_mustafa · Answer

I told in fraction form correctly..

shayaan_mustafa · Answer

$$f(x)=(11x ^{3}-9x ^{2}-10x)/(9-11x-10x ^{3})$$is this your fraction looks like?

anonymous · Answer

see attached

anonymous · Answer

yes

shayaan_mustafa · Answer

ok now.. as in your question. horizontal limits mean domain of the function.
DOMAIN:
it is where function is defined.
for example
if$$\lim_{x \rightarrow 0}1/x=\infty$$
because anything divided by zero, goes to infinity. so the function is not defined at infinity. so every number except this is its domain. because at 0 1/x is not defined.

shayaan_mustafa · Answer

got it ?

anonymous · Answer

sort of

anonymous · Answer

but the answer will be a set then?

shayaan_mustafa · Answer

yes. it will be a set.

anonymous · Answer

horizontal asymptote is the ratio of the leading coefficents, since the degree of the numerator and denominator are the same (they are both 3)

shayaan_mustafa · Answer

$$f(x)=(11x ^{3}-9x ^{2}-10x)/(9-11x-10^{3})$$In this function denominator must not be zero.

anonymous · Answer

therefore your horizontal asymptote is 
$$y=-\frac{11}{10}$$

anonymous · Answer

ok, my homework program does not accept  a set as the answer, it says that the answers must be a number

anonymous · Answer

and secondly - 11/10 is not being accepted either

anonymous · Answer

then there is a mistake, but i can assure you that is what it is
unless they want you to write 
$$y=-\frac{11}{10}$$

anonymous · Answer

im supposed to get 2 answers for this problem

anonymous · Answer

if -11/10 is one..whats the other?

mertsj · Answer

Did you double check to see if the problem is posted correctly?

mertsj · Answer

Or maybe they want it in decimal form.

anonymous · Answer

yes its correct

mertsj · Answer

What's correct?

shayaan_mustafa · Answer

it will define for all real numbers. X=all

anonymous · Answer

the problem was posted correctly

anonymous · Answer

i need 2 answers . if -11/ 10 is one, whats the other?

mertsj · Answer

I don't know.  Are they asking for the horizontal asymptotes?  Because there is only one.

anonymous · Answer

there is one, it is the ratio of the leading coefficients.  there is no other

anonymous · Answer

this is so complicated....:(

mertsj · Answer

Maybe they want you to say as x approaches positive infinity, the limit is -11/10 and as x approaches negative infinity, the limit is -11/10

anonymous · Answer

they are asking for horizonal limits...is this the same as horizontal asymptotes?

mertsj · Answer

Satellite???

anonymous · Answer

ok both answers are -11/10 and they did want it in decimal form. thanks guys

mertsj · Answer

yw.  I'll take the bows for Satellite's work.

shayaan_mustafa · Answer

as I have solved this equation

vertical asymptote= NO
horizontal asymptote= -11/10
oblique asymptote= NO

anonymous · Answer

$$f(x) = \frac {11 x^3 - 9 x^2 -10 x }{ 9 - 11 x - 10 x^3 }$$ is what is written, i cannot read the word document.
numerator is a polynomial of degree 3
denominator is a polynomial of degree 3 (same degree)
horizontal asymptote, limit as x goes to infinity, etc is 
$$y=-\frac{11}{10}=-1.1$$ the ratio of the leading coefficeints.  there is no other answer

anonymous · Answer

thanks so much

shayaan_mustafa · Answer

you are ever welcome.