Choose the value of the y determinant (Dy) in the system. x + 6y = –3 4x – 9y = 2 –33 –10 14 15
\[\begin{vmatrix}Dx&D&Dy\\1&-3&6\\4&2&-9\end{vmatrix}\]
I DONT GET IT , WHATS NEXT?
Do a cross like you would on vectors and you should have it; except the D would not need to go negative
im still confused , what do i divide
your not dividing; your taking the determinant of the submatrix associated with Dy
so what am i sapossed to do ?
... you sposed to take the determinant of the submatrix associated with Dy :/
i dont know how
then i spose youve asked the wrong question since the nature of this question presupposes that you have an inkling of an idea on what to do when asked for the value of Dy as the determinant of the indicated system
nevermind , i'll just guess
if we ignore the impertinent parts, we are left with this to base our solution on \[\begin{vmatrix}&&Dy\\1&-3&\\4&2&\end{vmatrix}\] assuming you know how to take the determinant of a 2x2 matrix that is
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