Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (2bornot2b):

If gcd(a,b)=1 then prove that gcd(ac,b)=gcd(c,b)

OpenStudy (anonymous):

HINT: (a,b) = 1 means that there is some x and y such that ax + by = 1

OpenStudy (anonymous):

perhaps start by writing \(d=gcd(ac,b)\) and \(e=gcd(b,c)\) and then show that \(d|e\) and \(e|d\)

OpenStudy (anonymous):

How about this: http://math.stackexchange.com/questions/20889/

OpenStudy (anonymous):

yes i guess that will do it. notice this fairly obvious fact actually takes a few lines to prove!

OpenStudy (anonymous):

Yes, sat, it's one of the many things of number theory which are just intuitively plausible.

OpenStudy (2bornot2b):

what do you mean @FoolForMath

OpenStudy (anonymous):

If you see Sivaram's answer, he has used the same fact I alluded to you :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!