Question

If \( a(p+q)^2+2bpq+c=0\) and \(a(p+r)^2+2bpr+c=0\) then qr = ?

Answer 1

can't wait to see this!

Answer 2

lol

Answer 3

This is a perfect candidate for my problem of the day.

Answer 4

Good one diya!

Answer 5

lol So how do i do it ?

Answer 6

Lol do you think I can answer everything just at sight? :P

Answer 7

i did :)

Answer 8

Is it \(\huge \frac{(ap^2 + c) }{ a} \) ?

Answer 9

Yup =D

Answer 10

gimmick is...?

Answer 11

Wo :D. It wasn't that hard as it look like :)

Answer 12

\[ a(p+q)^2 + 2bpq + c = 0 \implies aq^2 + 2p(a+b)q + ap^2 + c = 0 \]

and

\[ a(p+r)^2 +2bpr + c = 0 \implies ar^2 + 2p(a+b)r + ap^2 + c = 0 \]

can you see the rest? ;)

Answer 13

cool

Answer 14

I agree sat :)

Answer 15

ok let me see..

Answer 16

Don't see, observe :D I have to go now. It's nice solving your problems :)

Answer 17

\[aq^2+2p(a+b)q=ar^2+2p(a+b)r\]

Answer 18

\(q\) and \(r\) are the equation of \[ ax^2 + 2p(a+b)x + ap^2 + c = 0 \]

Answer 19

okay!

Answer 20

okay got it Thanks!!!

Answer 21

You are welcome, but I haven't done anything special.