Question

Two boats start their journey from the same point A and travel along directions AC and AD, as shown below.What is the distance, CD, between the boats?
115.5 ft
213.2 ft
230.9 ft
346.4 ft

Answer 1

tan(30) = BD/300
tan(60) = BC/300
BD-BC = CD

Answer 2

Are you studying trig? if so, sheena's answer is a good way. If you are studying special 30-60-90 triangles, then notice that triangle ABD is one of them. So you should be able to find leg AD: it is sqrt(3)*legAB

Triangle ABC is also a 30-60-90 triangle, so you should be able to find leg BC. BC is AB/sqrt(3)

Now you can find the distance between C and D. BD-BC

Answer 3

@iambatman @IMStuck can you help me find the answer to this please

Answer 4

I can help you. Let me draw it out to show you step by step, ok?

Answer 5

yes please :)

Answer 6

Find x first. Do this by using the cos of 60 degrees. Like this:

Answer 7

yes...

Answer 8

im understanding so far

Answer 9

tangent is the side opposite over the side adjacent so we will use the 600 + whatever the other distance is and find the whole distance BD by solving for y now.

Answer 10

im trying to process this one second

Answer 11

ok how do we solve for y

Answer 12

So the length of BD is the value for x + the value for y:
600 + (-80.3848)=> 600-80.3848=519.6152

Answer 13

yes but that is not one of the answer choices

Answer 14

@IMStuck

Answer 15

Oh boy then I have to redo. Hold on...sorry.

Answer 16

Duh...that's cuz I used cos in the first step and I should have used tangent! My fault!!! Redo! I'm going to delete the drawings and start over. So dumb...

Answer 17

no you are not dumb lol

Answer 18

NOW let's do this right!

Answer 19

yes!!