Question

solve for x

500e^(3x + 2) = 2500

Answer 1

e^(3x+2)=5
ln(e^(3x+2)=ln5
3x+2=ln5
x=(ln5-2)/3

Answer 2

nice

Answer 3

need explanation? feel free to ask!

Answer 4

i follow

Answer 5

what you did

Answer 6

glad i could help bro!

Answer 7

how did you get the 5 on the right side of the equation

Answer 8

dividing 2500 by 500

Answer 9

Divide both sides by 500 :)

Answer 10

2500/500= 500

Answer 11

No its 5

Answer 12

hahaha my calc is on drugs

Answer 13

i got it thanks

Answer 14

what about this

log2 x + log2 (x-2) = 3

solve for x

Answer 15

use brains as calc, usually better

Answer 16

and btw people can answer closed questions tooo (you asked that in chat)

Answer 17

log2 x*(x-2)=3
x^2-2*x=8
x'=4 x''=-2

Answer 18

no, did not use calc

Answer 19

just have a question about the 8, how did you get it?

Answer 20

log definition loga b=c <=> c^a=b
just did like 2^(log2 x*(x-2))=2^3

Answer 21

thanks

Answer 22

can you do this also

3ln(2x + 3) = 27

solve for x

Answer 23

ln(2x+3)=9
e^(ln(2x+3))=e^9
2x+3=e^9
x=(e^9-3)/2

Answer 24

3e^(1-x^2) times ln(x)

can you find the equation of the tangent line at x= 1

Answer 25

sorry, didn't see it! gonna see what i can do now

Answer 26

didn't understand very well what is asked, post it as a separate question?