Question

Find the general solution to the first-order differential equation 2x(y+1) - yy' = 0
will post choices

Answer 1

\[A) 2x ^{2}-y ^{2}\ln \left| y+1 \right|=C\]
\[B) x ^{2}(y+1)^{2}-y ^{2}=C\]
\[C)\ln \left| y+1 \right|+x ^{2}-y= C\]
\[D) x ^{2}=y+(1/(y+1)^{2})+C\]

Answer 2

@crzymom2u How?

Answer 3

@crzymom2u how?