Question

\[\int\limits_{}^{} \sec^{3}(x)\tan(x)dx\]

I tried
u = tan(x)dx
du/dx = sec^(2)(x)

but I'm left with sec(x)

How can I solve such a problem

Answer 1

integral of sec (x)=lnlsec(x)+tan(x)l+C

Answer 2

can you explain how to solve this?

Answer 3

do what you did, but just know that the integral of sec(x) is lnlsec(x)+tan(x)l+C

Answer 4

\[\int\limits\sec^{3}(x)\tan(x)dx\]

\[=\int\limits\sec^{2}(x)\sec(x)\tan(x)dx\]

let \(u=\sec(x)\), \(du=\sec(x)\tan(x)dx\)

Answer 5

thanks I got it now :)