Question

absolute maximum and minimum of 6x^2 - 2x + 5 = 14 years ago

Answer 1

6x^2 - 2x + 5, 0 =<x=<9

Answer 2

vertex is
\[-\frac{b}{2a}=\frac{1}{6}\] for the first coordinate, so minimum will be
\[f(\frac{1}{6})\] max will be
\[f(9)\]

Answer 3

what are the x values also? or at which x values will you find the absolute min and max