Question

Find the general solution for cos x = 0, where n is an integer.

Answer 1

Remember that the cosine is like x. So the cosine is 0 when the angle is 90 degrees or 270 degrees. Every trip around the circle will have cosine of 0 at those points so the solution is :
\[x=90, 270 +2\pi n\]

Answer 2

If you want it in terms of radians, it is:
\[x= \frac{\pi}{2}, \frac{3\pi}{2} + 2\pi n\]

Answer 3

The one in degrees should have been +360 n

Answer 4

can u help me with another one
3csc x=6

Answer 5

would the answer be pi/6 + 2pi n

Answer 6

and 5pi/6 + 2pi n

Answer 7

\[\csc x=2\]
\[\sin x=\frac{1}{2}\]
\[x=\frac{\pi}{6}, \frac{5\pi}{6}+2\pi n\]

Answer 8

Good for you. You got that one.

Answer 9

and for this one ten= \[\sqrt{3}\]

Answer 10

tan=\[\sqrt{3}\]

Answer 11

is the answer pi/3 + npi

Answer 12

\[x=\frac{\pi}{3}, \frac{4\pi}{3} + 2\pi n\]

Answer 13

Yes. You could just say pi/3 +n pi. It would be the same thing.

Answer 14

and 2 more question: i just want to make sure

Answer 15

ok

Answer 16

If you wanted to solve the equation 2sin x = 1, then you could find the solutions by looking at

Answer 17

here are the options:

the x-intercepts of y = 2sin x - 1
the y-intercepts of 2sin x = 1
the y-intercepts of y = 2sin x - 1
the x-intercepts of 2sin x = 1

Answer 18

The first one.