Hi, it says to use the substitution method.... 3x+5y=3/5 y=5x-1
I just want to know what to do. I have never done one before
this kid's gonna help you real good dunworry :D taught him myself hahaha jk
seems he's putting very much details into this..just be patient :D seems like it's gonna be good
igba is right
Method of substitution means that we have to put x=.... or y=.... onto one equation which is in terms of x and y to eliminate one of the variables in order to solve the equation So y=5x-1 can help us elimnate y in 3x+5y=3/5. Sub y=5x-1 into 3x+5y=3/5 3x+5(5x-1) =3/5 3x+25x-5=3/5 28x-5=3/5 28x=28/5 x=1/5 we can now get the value of x. Don't forget that we have to find y also. So, put x=1/5 into y=5x-1, y=5(1/5)-1=0 The answer is x=1/5 and y=0
there we go :DD
how did you get 28/5???
28x-5=3/5 as we want to find x so we want the answer to be expressed in x=... first, to cancel -5 on LHS, 28x-5+5=3/5+5 28x = 28/5 there is 28 on LHS. We have to cancel it 28x/28=(28/5)/28 x=1/5
3/5 + 25/5 = 28/5...additional info ^_^
thank you so much
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