A manufacturer of graphing calculators has determined that 15,000 calculators per week will be sold at a price of $96. At a price of $94, it is estimated that 15,740 calculators would be sold. (a) Determine a linear function that will predict the number of calculators y that would be sold at a given price x.
Hint: apply slope formula 2nd Hint: apply point-slope formula
3rd Hint: \[(x_1, y_1) = (15,000, 96)\]\[(x_2, y_2) = (15,740, 94)\]
so 15000-15740/94-96
well the answer I had in the end was 740/-3
m = 740/-2 = -370
ok thats where I think I was going wrong. Been a late night
so then the next step would be -370x+b?
Nevermind, we both made the same mistake
It's correct except, we both had the wrong setup
ok so its not -370?
\[\frac{96 - 94}{15000 - 15740}\]
No, it's not -370.... that's what I meant by "wrong setup"
ok so 2/-740
or - 1/370 always simplify to lowest terms
ok and I take that to x and add it to what? the y1?
No, that's our m = slope, value
We need to apply this formula: \[y - y_1 = m(x - x_1)\]
ok now I see where I am at
\[y - 15000 = -\frac{(x-96)}{370}\]
\[y - 15000 = \frac{96 - x}{370}\]
then add the 1500 to both sides correct
\[y = \frac{96 - x}{370} + 15000\]
We can simplify that a little further
ok
48-x/185?
What did you do with the 15,000?
That's the formula expressed in terms of one fraction
I have not done anything yet but I will add it to the total minus x
ok
Hold on let me double check my work
You should re-post the question. I must not have the right approach here because something is off
Yeah, I think the x and y should be flipped
It's the price that determines how many calculators will be sold. I apologize
so m = -370
ok
Yeah, plus I mixed up the x and y while computing using the point-slope formula again. It's easy to get mixed up. I kept thinking the y value was 15,000 even though I was supposed to have 96 for the y value.. ugh
ok got it its: -370x+50520
Yes, that's it
I submitted it and its correct. Thank you for your help
Yes, it is correct
thank you for your time and help
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