A golf ball is struck at ground level. The speed of the golf ball as a function of the time is shown in Figure 4-36, where t = 0 at the instant the ball is struck. The scaling on the vertical axis is set by va=16 m/s and vb=32 m/s. (a) How far does the golf ball travel horizontally before returning to ground level? (b) What is the maximum height above ground level attained by the ball?
Without the Figure , this can't be tackled. Sorry.
there it is
a= 2.5 b.=4
what do you mean by va and vb
the graph shows that the velocity reaches a minimum at t=2.5 secs At this point the vertical velocity is zero, and all of the velocity is horizontal. Vx= 16 m/s Neglecting air friction, we assume Vx is constant over the entire time interval. So use S= Vx * t = 16 m/s * 5 s = 80 m for the horizontal distance.
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