Question

How do I solve:

tan^2(x)-3tan(x)+2=0

Answer 1

let tanx=u then it's u^2-3u+2=0
or u = 1, 2

or tanx=1 => x = pi/4
or tanx = 2 => x= arctan(2)

Answer 2

let tan x =A
A^2-3A+2=0
now solve it??

Answer 3

tan^2(x)-3tan(x)+2=0
(tan(x)-2)(tan(x)-1)=0

tanx=2 , tanx=1
x=45, 63.43 , 243.43 , 225

Answer 4

it would probably help if you let tan(x) = u

u^2 -3u + 2 = 0

solve the quadratic function..then substitute u back to tan(x)..arctangent the values to get x :DDD

Answer 5

thanks guys, I get tanx=1 equals pi/4 and 5pi/4 because of the unit circle but how would I find the values of tanx=2 on that?

Answer 6

tanx=2 must use calculator

Answer 7

Alright I really appreciate everyone's help! you're are the best :)