Question

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Answer 1

This is:

1) Identical to the question you asked previously.
2) Looks like it's taken directly from a graded assignment.

Answer 2

guess it was not clear the first time, do you have a specific question?

Answer 3

http://openstudy.com/users/eli123#/updates/4f78784de4b0ddcbb89e3e89

Answer 4

your job now is only to evaluate
\[32(\cos(\frac{\pi}{2}+i\sin(\frac{\pi}{2}))\] which comes down to evaluating
\[\cos(\frac{\pi}{2})\] and
\[\sin(\frac{\pi}{2})\] and multipling the result by 32

Answer 5

i got it the first time, the problem is that the website where im doing the homework keeps telling me that the answer is wrong

Answer 6

well cosine of \(\frac{\pi}{2}\)=0 and \(\sin(\frac{\pi}{2})=1\) so you should get 32i

Answer 7

wait so 32 is the imaginary?

Answer 8

it is
\[32(0+i)=32i\]

Answer 9

and 0.279 is the real number?

Answer 10

there is no real part

Answer 11

i am not sure where you are getting the numbers from
\[\cos(\frac{\pi}{2})=0,\sin(\frac{\pi}{2})=1\]

Answer 12

you have
\[2^5(\cos(\frac{\pi}{2})+i\sin(\frac{\pi}{2}))=32(0+i)=32i\]

Answer 13

if you are using a calculator to evaluate (looks like it) make sure to put it in "radian" mode and then use exact (not decimal) numbers for your input

Answer 14

http://www.wolframalpha.com/input/?i=cos%28pi%2F2%29

Answer 15

thats why i was getting it wrong

Answer 16

when i have a 30' in an equation , what does that mean?radians?