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If the point P(-3/5y) lies on the unit circle and (P) is in the second quadrant, what does (y) equal? HELP DX
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unit circle points satisfy this relation: \[\sqrt{x ^{2}+y ^{2}} =1\] so: \[\sqrt{(3/5)^{2}+y ^{2}} = 1\] solve this equation for y. You will get 2 values of y which are bouh correct
@jCortez93
if you have problem solving it, tell me
How do you solve it?
square bouth sides and you get: \[3/5^{2}+y ^{2} =1\] so: \[y= \pm \sqrt{1-9/25}=\pm \sqrt{16/25} =\pm 4/5\]
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