Question

A ball is dropped from a height of 300 feet. Its velocity after t seconds is v=-32t ft/s
A) How fast is the ball dropping after 4 seconds (i got -128, i want to make sure)
B)Determine the position function
C) How far has the ball dropped after 4 seconds
D)How many seconds will it take for the ball to hit the ground

Answer 1

lol. it classical physics.
you should post in physics group.

Answer 2

...this is calculus

Answer 3

is this? which book?

Answer 4

ok let us solve this. be here.

Answer 5

calculus seventh dition

Answer 6

howard anton?

Answer 7

Larson Hostetler Edwards

Answer 8

the velocity is slowing down after you drop it?

Answer 9

acceleration due to gravity is defined in feetric measure as:

-32ft/^2 a constant rate so:

a(t) = -32

velocity is the integration of acceleration:

{S} a(t) = v(t) = -32t + c , and we are given that at t=4 v= -32

-32 = -32(4) + c

-32+32(4) = c

32(4-1) = c = 96

v(t) = -32t +96

the integration of velocity gives us position

{S} v(t) = h(t) = -16t^2 +96t +c

Answer 10

no the negative would mean that the ball is heading toward the earth

Answer 11

yeah, i saw that afterwards :)

when time (t) = 0 we are at a height of 300 sooo

300 = -16(0)^2 + 96(0) + c ; hence c = 300

h(t) = -16t^2 +96t +300

Answer 12

i got some of the information mixed up fromthis tiny little screen

Answer 13

the 96 is bad; spose we are simply dropping the ball; giving it no initial velocity; the that part goes to 0

Answer 14

h(t) = -16t^2 + 300

v(t) = -32t

a(t) = -32

Answer 15

so v(4) = -128

Answer 16

the rest of it is just filling in the numbers i believe

Answer 17

so what is the velocity in the position function?

Answer 18

initial velocity is zero inthe position function

Answer 19

if we throw the ball; that gives it an inital velocity other than zero; simply letting it drop imparts no velocity and lets gravity do all the work

Answer 20

ok i got it thanks

Answer 21

yw