Question

find d/dx of f^(-1) (x)

Answer 1

what is the value of x?

Answer 2

x/x + 1

Answer 3

is f(x) = x/x + 1?
or is f^-1(x)= x/x +1?

Answer 4

d 2

Answer 5

f^(-1) x = x/x+1

Answer 6

well in any case, use the quotient rule

where if you a function h defined as f/g

then d/dx h = (f' * g - f * g') / g^2

Answer 7

..............x
f(x) = -------------
..........x + 1
........x
y = --------
......x + 1
........y
x = --------
......y + 1

x(y + 1) = y
xy + x = y
xy - y = - x
y(x - 1) = - x
...........x
y = - ---------
.........x - 1
.................x
f⁻¹(x) = - ----------- answer//
................x - 1


bye..

Answer 8

nope

Answer 9

i got dat but it wasn't d ans

Answer 10

you need to use the quotient rule next:

x = f, x+1 = g

d/dx x/x+1 =

[1(x+1) - x(1)]/(x+1)^2

1/(x+1)^2

Answer 11

yeah i got it now but it wasnt ur ans funinabox it was 1/(1-x)^2

Answer 12

thank u all

Answer 13

then you typed the problem wrong

Answer 14

no it was correct

Answer 15

then the answer is wrong

1/(1+x)^2 is the correct answer.

Answer 16

but i got the marks

Answer 17

i think i know what's up

f(x) = x/x + 1
it's not f^-1(x) = x/x + 1 as was stated

that way, when you do find the inverse, you get x/1-x, which would give you the derivative you posted.