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State the Domain and range of the function f(x)=[2e^(x+3)+7] in interval notation.
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checking out
a) Domain: (-INF,INF) Range: (0,INF) b) Domain: (0,INF) Range: (-INF,INF) c) Domain: (-INF,INF) Range: (7,INF) d) Domain: (-INF,INF) Range: [7,INF) e) Domain: [3,INF) Range: (-INF,INF)
heavy 4 me
domain is all real numbers since you can raise e to any power at all
and since no matter what x is, we know \(e^x>0\) that means \(2e^{x+3}+7>7\)
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as usual, the answer is C
thats fantastic satellite
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