Question

Please Solve:
(-2+8i)/(-4+4i)

Answer 1

expand?
FOIL just like you would if they were real numbers, remembering that i^2=-1
8-8i-32i+32i^2=8-40i-32=-24-40i

Answer 2

But dividing wouldnt it be less in fraction?

Answer 3

oh i didnt see the division sign

Answer 4

Then it would be... 1+4i/2 ???

Answer 5

\[\frac{-2+8i}{-4+4i}*\frac{-4-4i}{-4-4i}\]

Answer 6

multiply top and bottom by
\[-4-4i\] because
\[(a+bi)(a-bi)=a^2+b^2\] a real number

Answer 7

mhm

Answer 8

what .sam. said
denominator will be
\[4^2+4^2=32\] all the work is multiplying in the numerator

Answer 9

but the result would be 1+4i/2 ???