Question

3x^2-2x-5?

Answer 1

Please help with quadratic formula!

Answer 2

solving... what are you trying to do?

Answer 3

number 10.

Answer 4

yes, solve.

Answer 5

\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 6

3x^2 = 2x+5

3x^2-2x-5 = 0

(3x-5) (x+1) = 0

3x-5=0, x+1=0

x=5/3 , x=-1

x=1,66, x=-1

Answer 7

\[3x ^{2}-2x-5\]
\[3x ^{2}+3x-5x-5\]
\[3x(x+1)-5(x+1)\]
\[(3x-5)(x+1)\]
\[x=5/3\] OR
\[x=-1\]

Answer 8

Thank You a Sakigirl

Answer 9

solving... ok that are multiple ways to do this and as you continue in your education in math you will find which one you like best... in this case i recommend the quadratic formula

which is

where

3x*2 -2x -5
A B C

you just plug in the coefficients (numbers in front of the x)

or you can factor

i will use an example x^2 +2x + 1