Question

If f(x) + x^2 * f(x) = 10 and f(1)=2, find f'(1).

Answer 1

check ur ques. again
its wrong
it does not satisfy for f(1)=2 in the main equation

Answer 2

well that's the friggen problem verbatim from the textbook

Answer 3

OH pellet

Answer 4

it's not sorry geez sorry it's f(x) + x^2 * f(x)^3 = 10 the second f(x) term is cubed

Answer 5

Maybe rearrange the problem a bit....\[y+x^2y=10\implies y=\frac{10}{1+x^2}\]I don't think your problem meets the specified conditions.

Answer 6

is ur anwer 2/5??

Answer 7

it's -16/13 that's the answer in the book

Answer 8

animalain - it's y + (x^2)(y^3) = 10

Answer 9

Yeah, I got that. Trying to figure out my strategy....

Answer 10

yeah its done

Answer 11

...

Answer 12

How did you do it?

Answer 13

differentiate it n then put x=1 in equation
u'll get the result

Answer 14

is that done??

Answer 15

\[y + (x^2)(y^3) = 10\implies y'+2xy^3+3x^2y^2y'=0\]\[\implies y'(1+3x^2y^2)=-2xy^3\implies y'=\frac{-2xy^3}{1+3x^2y^2}\]\[\implies y'(1)=\frac{-16}{13}\]Got it. Need to practice my calculus a little more....LOL

Answer 16

all the best..:)