Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

how to simplify (1x-3)/(5x^2 + 5x -60) ???

OpenStudy (lgbasallote):

try factoring out the numerator and the denominator..what factors would you get?

OpenStudy (anonymous):

see if that denominator can be factored first. take out a 5...

OpenStudy (anonymous):

yeah 5 so (x-3)/ 5(x^2 + x - 12) ?

OpenStudy (lgbasallote):

seems x^2 + x -3 can be factored as well...try factoring it out..

OpenStudy (anonymous):

im not sure how but would you take the x out? D:

OpenStudy (lgbasallote):

no..you factor out binomials..

OpenStudy (anonymous):

hmm

OpenStudy (perl):

its a trinomial in the denominator

OpenStudy (perl):

(1x-3)/(5(x-3)(x+4))

OpenStudy (anonymous):

ohhhhh

OpenStudy (perl):

(x-3) -------------- 5 ( x-3)(x+4)

OpenStudy (perl):

now see if you can cancel. (please give me medal. )

OpenStudy (perl):

yay!!

OpenStudy (anonymous):

okay so 5(x +4)?

OpenStudy (anonymous):

wait 1 / that?

OpenStudy (anonymous):

yay it is thanks guys!

OpenStudy (perl):

anything else?

OpenStudy (anonymous):

it says express this as single fractions in its simplest form : 1/x + 2/(x+4)

OpenStudy (perl):

we need to find a common denominator first,

OpenStudy (anonymous):

i simplified it and i got 3x + 4 but the answer is 3x +4 / (x(x+4)) :(

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

??

OpenStudy (perl):

so we know that

OpenStudy (perl):

the common denominator is x(x+4) , agreed?

OpenStudy (anonymous):

yep :)

OpenStudy (perl):

ok so now we have to make each term have that denominator

OpenStudy (anonymous):

yep

OpenStudy (perl):

we know that we can multiply the first fraction by (x+4)/(x+4) which is the same thing as multiplying by 1 (so its a legal operation)

OpenStudy (perl):

and we can multiply the second term by x/x ,again the same thing as multiplying by 1. so its legal

OpenStudy (anonymous):

hmmm

OpenStudy (perl):

1 (x+4) 2 ( x) -- * ---- + ---- * ---- x (x+4) (x+4) ( x)

OpenStudy (perl):

its legal in the sense that multiplying by 1 does not change the number , we are only changing it's 'form' , to make it easier to manipulate or add

OpenStudy (anonymous):

oh okay yep

OpenStudy (perl):

|dw:1333352449764:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!