Question

A problem
Solve for x,

7.3^(x-1)+5-3^(x+1)=0

Answer 1

\[\huge 7.3^{x-1}+5-3^{x+1}=0\]

Answer 2

is that 7*3^(x-1) or (7.3)^(x-1)

Answer 3

decimal

Answer 4

hmmm, doesnt look easy

Answer 5

do tell me..does this involve canceling 3^x-1 the solution i thought had that..

Answer 6

\[3^x = \frac{15}{2}\]
\[x = \log_3 \frac{15}2\]

Answer 7

@Ishaan94 that's true if the decimal was "dot" *

Answer 8

Oh, my bad... so it's
\[(7.3)^{x-1} + 5-3^{x+1}=0\]Hmm Now I feel stupid :/

Answer 9

ok I have an idea