Find the vectors perpendiuclar to both of the given vectors.\[\left(\begin{matrix}8 \\ -3\\ 1\end{matrix}\right)and\left(\begin{matrix}7 \\ -2\\ 0\end{matrix}\right)\]
make a vector product of them and you got it
What's a vector product?
v X u =w
vector cross product .. thats the best way.
(2,7,5) is the answer
http://upload.wikimedia.org/wikipedia/en/math/0/9/b/09bf9d6c78c3c975a2b5ae76fbe504b9.png
this is actualy a question related to the one you asked befor about the plane. You are looking here for the equation of the plane that contains bouth of this vectors, :)
I can't see that link very clearly, and don't understand it. Can you write it out in full here?
k, wait
I understand it. Don't worry :)
this is the way you calculate vector cross product. You will get a vector that is perpendicular to bouth of them
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