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determine the volume of the solid obtained by rotating the region bounded by x=(y-2)^2 and y=x about the line y=-1
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well we can apply the formula \[\pi \int\limits_\int\limits_^{2dy} \]
Then you use disc method?
callisto first we need to take square of equation, integrate it , then put the limits
Would you mind showing the them all? (Sorry, I'm not the asker of this question though)
ok wait
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squaring the eq gives, (y-2)^4 now we need to integrate which gives us \[{(y-2)^5}/5\]
now put the limits -1,0
Sorry, but how do you find limits to be -1, 0?
yeah i guess i should draw the picture
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