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given the rate equation rate=k[a]^-2[b] what are the units for k.
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rate is typically expressed in terms of mol/L*min, or \[R = \frac{mol}{L*\min}\] or some other unit of time. That rate has to also be equal to the rate law, which you've been given as \[R = k \frac{[B]}{[A]^{2}}\] the units of K have to be such that when you multiply by the concentrations, you're left with only mol/L*min
I find it unlikely that you would have a negative second order though.
@shamalamadingdong true, but if it were, that would get you the proper units for k.
I agree that's why I gave you a medal.
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