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Mathematics 8 Online
OpenStudy (anonymous):

Find the limit as x approaches 0 of: x^2 + cosx

myininaya (myininaya):

Did you plug in 0? :) This function is continuous at x=0 so you may do so

OpenStudy (anonymous):

Why do you do that?

OpenStudy (anonymous):

because it is easiest

OpenStudy (anonymous):

if \(f\) is continuous then \(\lim_{x\to a}f(x)=f(a)\)

OpenStudy (anonymous):

Okay, but is there another way to do this? Like with identities?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

How do you know it is continuous?

myininaya (myininaya):

f(0) exists

myininaya (myininaya):

and the functions is continuous everywhere

myininaya (myininaya):

because x^2 is continuous everywhere and cos(x) is continuous everywhere

OpenStudy (anonymous):

every function you know that is definded on an interval is continous on its domain

OpenStudy (anonymous):

sine, cosine, exp, log, any polynomial, any rationa function etc all continuous on their domains

OpenStudy (anonymous):

okay but if it were something like sinx/x it would not be continuous because x is undefined at 0?

OpenStudy (anonymous):

even that one is continous on its doman. just happens that the domain does not include zero

OpenStudy (anonymous):

limit exists at x = 0, but the function does not, so it is not continous at 0 in order for a functioni to be continuous at a point "a" it must be defined at "a"

OpenStudy (anonymous):

okay thanks:)

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