Find the limit as x approaches 0 of: x^2 + cosx
Did you plug in 0? :) This function is continuous at x=0 so you may do so
Why do you do that?
because it is easiest
if \(f\) is continuous then \(\lim_{x\to a}f(x)=f(a)\)
Okay, but is there another way to do this? Like with identities?
no
How do you know it is continuous?
f(0) exists
and the functions is continuous everywhere
because x^2 is continuous everywhere and cos(x) is continuous everywhere
every function you know that is definded on an interval is continous on its domain
sine, cosine, exp, log, any polynomial, any rationa function etc all continuous on their domains
okay but if it were something like sinx/x it would not be continuous because x is undefined at 0?
even that one is continous on its doman. just happens that the domain does not include zero
limit exists at x = 0, but the function does not, so it is not continous at 0 in order for a functioni to be continuous at a point "a" it must be defined at "a"
okay thanks:)
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