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Mathematics 12 Online
OpenStudy (anonymous):

why is this true?

OpenStudy (anonymous):

which one?

OpenStudy (anonymous):

limit of tanx/x = 1

OpenStudy (anonymous):

when x approaches 0

OpenStudy (anonymous):

apply the expansion of tan x

OpenStudy (anonymous):

what is the expansion? can u explain?

OpenStudy (anonymous):

u will find it here: http://en.wikipedia.org/wiki/Taylor_series

OpenStudy (anonymous):

How to do it without expansions? I havent learned that yet.

OpenStudy (anonymous):

\[\lim_{x \rightarrow 0}(tanx/x)= \lim_{x \rightarrow 0}(sinx/x)/cosx\]

OpenStudy (anonymous):

we know, lim x tends to 0, sinx/x =1 and cosx=1 so, combining, we can get 1/1=1

OpenStudy (anonymous):

Im not really sure how you got from limx→0(tanx/x)=limx→0(sinx/x)/cosx

OpenStudy (anonymous):

because tan x= sin x/cos x

OpenStudy (anonymous):

whats the problem here ?!

OpenStudy (anonymous):

why is |dw:1333430183693:dw|

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