Question

radical expression simplfy

Answer 1

\[\sqrt{14q}* 2\sqrt{4q}\]

Answer 2

factor out sqrt (14q) and sqrt (4q) individually first. im sure youll get some idea after

Answer 3

any factors

Answer 4

hmmm let's start with sqrt (4q)...it's equal to sqrt (4) times sqrt (q) what do you notice?

Answer 5

2 and 2

Answer 6

hmm good observation..so it's 2^2 right? sqrt (2^2) = 2 yes?

so it's sqrt (14q) + 2(2)(sqrt q)

you can factor out sqrt q here...

sqrt q (sqrt 14 + 4)

Answer 7

@lgbasallote 4q sqrt14q

Answer 8

sqrt14 w/o q

Answer 9

oh wait it's multiplication o.O

Answer 10

so is it 3 sqrt56q^2

Answer 11

or is it a 2

Answer 12

lemme repeat that
2 (sqrt 4q) = 4 sq (q)

4 sq (q) times sqrt 14 q

= 4 sqrt (14q^2)

= 4q sqrt 14

Answer 13

can u simplify sqrt 144 i put 12 it was wrong

Answer 14

sqrt 144 = 12

Answer 15

\[-2 \sqrt{2p}*2\sqrt{22}\]

Answer 16

Whats this

Answer 17

Starting with
\[ \sqrt{144q}\cdot 2\sqrt{4q} \]
Look for perfect squares (if you know your times table up to 12 times 12, then you know 12^2 = 144 and 2^2= 4) Take the square root of the perfect squares. We get
\[ 12\cdot 2 \cdot 2\cdot \sqrt{q}\cdot \sqrt{q} \]
Of course \( \sqrt{q} \cdot \sqrt{q} = q \) and the simplified expression is
48q

Answer 18

where u get 144 that was another question

Answer 19

@phi where u get 144 that was another question

Answer 20

If the problem is
\[ \sqrt{14q}\cdot 2\sqrt{4q} \]
then you get
\[ 2\cdot 2 \cdot \sqrt{14}\cdot \sqrt{q}\cdot \sqrt{q} \]
which simplifies to
\[ 4q\sqrt{14} \]