Question

find the complex zeros of f(x)=x^4+15x^2+14. Write f in factored form.

Answer 1

x^4+15x^2+14 =0
(x^2+1)(x^2+14)=0
x^2+1 =0 or x^2 +14 =0
x^2+1-1=0-1 or x^2 +14-14=0-14
x^2=-1 or x^2=-14
x=i or -i or 14i or -14i

Answer 2

f(x)=x^4+15x^2+14 =(x-i)(x+i)(x-14i)(x+14i)

Answer 3

that answer is coming up as incorrect

Answer 4

(x-i)(x+i)(x-14i)(x+14i) = (x^2+1)(x^2 +14) = x^4 +15x^2+14

what's the answer given?

Answer 5

i don't know. i have to solve it. it just comes up as incorrect

Answer 6

What are your steps?

Answer 7

they don't give me any steps its just shown like i typed it in the beginning

Answer 8

Oh, i see. So, why you think "that answer is coming up as incorrect" ?

Answer 9

should be isqrt(14), -isqrt(14)

Answer 10

because this is a homework assignment that i'm doing on a website and the program is showing the answer in incorrect.

Answer 11

try
\[(x-i)(x+i)(x-i \sqrt{14})(x+i \sqrt{14})\]

Answer 12

I found my mistake!
x^4+15x^2+14 =0
(x^2+1)(x^2+14)=0
x^2+1 =0 or x^2 +14 =0
x^2+1-1=0-1 or x^2 +14-14=0-14
x^2=-1 or x^2=-14
x=i or -i or isqrt 14 or -isqrt 14

Answer 13

sorry for making mistake

Answer 14

its ok thanks tho