Question

Use properties of logarithms to expand the following expressions.

log1 6y I dont know what to do...

Answer 1

hmm..first ask yourself..do you see any operation her? (+, -, x, /)

Answer 2

I think this is the same as saying 6y to what power equals 1

Answer 3

i see multiplication

Answer 4

good! @Geometry_Hater and that means....? @IAmCorbin it's 1 raise to something equals 6y

Answer 5

i dont know .....you multiply 6y by something?

Answer 6

what power do you raise 1 to to get 6y?

Answer 7

log_a (bc) = log_a b + log_a c

any ideas now?

Answer 8

6?

Answer 9

log1(6) + log1(y) = log1 (6y)

Answer 10

is that the answer?

Answer 11

that still needs to be solved

Answer 12

what do i do to that then

Answer 13

I'm not sure what to raise 1 to to get 6

Answer 14

my paper just says log 6y

Answer 15

which is the same as log(6) + log(y) according to @lgbasallote

Answer 16

yeah this is where my mind goes blank

Answer 17

I don't know if this problem can be simplified anymore. One raised to anything is always 1

Answer 18

that's the simplest it gets