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OpenStudy (anonymous):
find two intergers whose product is 105 such that one of the intergers is one more than twice the other interger. I have (n+1)(2n)=105. then from there I have 2n^2+2n-105=0.Am i on the right track?
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OpenStudy (anonymous):
Not quite. One more than twice the other is gives the expression 2x+1. So you have \[x(2x+1)=105\]
OpenStudy (anonymous):
oh duh! thank you!
OpenStudy (anonymous):
No sweat.
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