Question

find two intergers whose product is 105 such that one of the intergers is one more than twice the other interger. I have (n+1)(2n)=105. then from there I have 2n^2+2n-105=0.Am i on the right track?

Answer 1

Not quite. One more than twice the other is gives the expression 2x+1. So you have \[x(2x+1)=105\]

Answer 2

oh duh! thank you!

Answer 3

No sweat.