Apply L'Hôpital's Rule to evaluate the following limit. It may be necessary to apply it more than once.

lim x-inf (x-6)/(5-8x)

Question

Apply L'Hôpital's Rule to evaluate the following limit. It may be necessary to apply it more than once.

lim x->inf   (x-6)/(5-8x)

laddiusmaximus · Answer

why would that be on the bottom?

laddiusmaximus · Answer

walk me through it please

anonymous · Answer

L'Hôpital's Rule is when you take the derivative of the top and bottom and then evaluate the limit if it is at x=>0, inf, or -inf. The derivative of this is found using the quotient rule. Not sure if you don't know L'Hôpital's Rule or the quotient rule. If you don't know the quotient rule I'll be happy to explain =)

laddiusmaximus · Answer

I know the quotient rule. I wasnt sure how you got -1/8

anonymous · Answer

The little mark means the derivative

amistre64 · Answer

whats the derivative of the top?

laddiusmaximus · Answer

1

amistre64 · Answer

whats the deriveative of the bottom?

laddiusmaximus · Answer

8

amistre64 · Answer

forgot a sign with that, look again

laddiusmaximus · Answer

-1/8

amistre64 · Answer

$$L'Hop=lim\frac{t'}{b'};\ \lim_{x\to inf}\frac1{-8}=-\frac{1}{8}$$

anonymous · Answer

Ahh! Completely forgot it was different. He's right, take the derivative of the top and bottom *separately*, sorry about that.

laddiusmaximus · Answer

no worries. have a new one if you are interested