Question

sqrt6m - 5 = m

Answer 1

plz write it with help of equation

Answer 2

for better help go to - http://www.physicsforums.com/archive/index.php/t-9474.html

Answer 3

\[\sqrt{6m} - 5 = m\]

Answer 4

impossible man!!

Answer 5

imaginary number..

Answer 6

@Arnab09 what do u say

Answer 7

wait im confused

Answer 8

imaginary number... @Rohan

Answer 9

square every term

then

6m - 25 = m^2

m^2 - 6m + 25 = 0

solve the quadratic

Answer 10

sqrt(6m) -5 =m
sqrt(6m)=m+5 <--- put sqrt at one side
6m=(m+5)^2 <----- square both side
6m=m^2 +10m +25 <--- expand right hand side
6m-6m= m^2 +10m +25 -6m
0= m^2 +4m+25

b^2-4ac = (4^2)-4(1)(25) = 16-100=-84<0
Therefore, no real solutions

m^2 +4m+25=0
(m^2 +4m +4)-4 +25=0
m^2+4m+4 +21=0
(m+2)^2 +21-21=0-21
(m+2)^2 =-21
m+2 =isqrt21 or -isqrt21
m=-2+isqrt21 or -2-i sqrt21

Answer 11

A.{1}
B.{5}
C.{1, 5}
D.no real solution
there are the answer choices

Answer 12

The answer is D according to my steps shown before :D

Answer 13

ok thankj you very much :D

Answer 14

thank*

Answer 15

\[\sqrt{6m}=m+5\]
\[(\sqrt{6m})^2=(m+5)^2\]
\[6m=m^2+10m+25\]
\[m^2+4m+25=0\]
\[m=\frac{-4 \pm \sqrt{4^2-4(1)(25)}}{2(1)}\]
\[m=\frac{-4 \pm \sqrt{-84}}{2}=\frac{-4 \pm \sqrt{84i^2}}{2}=\frac{-4 \pm 2i \sqrt{21}}{2}=-2 \pm i \sqrt{21}\]