Question

integral of (1/((2x-1)^1/3)) dx

Answer 1

\(u=2x-1, du =2dx,\frac{1}{2}du = dx\) then integrate
\[\frac{1}{2}\int u^{-\frac{1}{3}}du\]

Answer 2

so would it be 1/2 ln| (2x-1)^1/3| + c

Answer 3

?

Answer 4

no

Answer 5

there is no log here, use the power rule backwards

Answer 6

\[\int u^{-\frac{1}{3}}du=\frac{3}{2}u^{\frac{2}{3}}\]

Answer 7

So then its 3/4 (2x-1)^2/3

Answer 8

?