Question

use the quadratic formula to solve :
2x^2-5x=1

Answer 1

\[5\pm \sqrt{17}/4\]

Answer 2

\[-b \pm \sqrt{b^2-4ac}/2a is your general form of \] is your general form of quadratic eq

Answer 3

is that...
\[5+\sqrt{17}/4 \] as in 5+or- (sqrt) 17 over 4?

Answer 4

yeah

Answer 5

is the answer satisfactory ?

Answer 6

2x^2 -5x =1
2x^2 -5x -1 =0
x_1,2 = (5+/- sqrt(25+8)/4 = (5+/- sqrt33)/4

Answer 7

yes it is