Question

Find the point of the parabola y=x^2-4x+3 where the tangent is parallel to the line 3x+y=2. Determine the equation of the tangent at that point.

Answer 1

Find the first derivative of the parabola. That is the slope function. The slope of the given line is -3. So set your slope function equal to -3 and solve for x. Then replace x with that number in the parabola's equation to find the y coordinate of the point. Then use point-slope form to find the equation of the tangent.

Answer 2

the derivative i got was 2x-4

Answer 3

y - (5/4) = -3 ( x -1/2)

Answer 4

What did you do? I dont understand

Answer 5

Follow Mertsj's instruction:
Set the derivative = - 3
=> x = ...

Answer 6

where did you get 5/4?

Answer 7

Plug x back to f(x)