Question

What is the probability of rolling a 4 twice in a row with a six-sided die, numbered 1 through 6?

Answer 1

oh.... ok i think that helps.... thanks!

Answer 2

i think it might be \(\frac{1}{6}\times \frac{1}{6}\)

Answer 3

i read it as "rolling a "4" twice in a row"

Answer 4

yeah its 1/6....

Answer 5

actually it is \(\frac{1}{36}\)

Answer 6

With who?

Answer 7

It's 1/6 * 1/6, like satellite73 said

Answer 8

I believe it means rolling a number 4 twice:
P ( 4 and 4) = 1/6 * 1/6 = 1/ 36

Answer 9

The first problem clearly states either heads twice OR tails twice. Which is something different.

There two outcomes are looked at. This problem looks at one outcome, namely 4 rolled twice

Answer 10

it is 1/36

Answer 11

I also agree that it is 1/36
The first time you row, you need to get a 4 , so
P(4) = 1/6
The second time you row, you need to get a 4 , so
P(4) = 1/6
Since you need to get a '4' in the first time AND the second time
P(4 and 4) = 1/6 x1/6 = 1/36

For the example given by Luis,
P(both head) = 1/2 x 1/2 = 1/4
P(both tail) = 1/2 x 1/2 = 1/4
Since it requires either both tails OR both head
P(both tails or both heads) = 1/4 +1/4 = 1/2