Question

List two points on the parabola -> x=y^2-2

Answer 1

here it's best to choose any y-value to get the x value... try y=0....

Answer 2

Huh? What y values can i choose?

Answer 3

i would choose ones that fit on your graph, y=0 is a easy choice, and a good choice, but you can choose any real number for y

Answer 4

i dont understand this at alll. So would (-1,0) be a point?

Answer 5

\[x=y^2-2\]
if you set y=0
\[x=0^2-2\]\[x=-2\]
so (x,y) =(-2,0) is a point that satisfies the equation of this parabola

Answer 6

now set y=1
\[x=1^2-2\]\[x=1-2\]\[x=-1\]so (-1,1) is also a point that satisfies the parabola

Answer 7

try y=2
what do you get for x?

Answer 8

x=2^2-2
x=4-2
x=2
(2,2)
right?

Answer 9

right, !
you can try any value for y and you will find a value for x
these order pairs (x,y)s are all points on the parabola

Answer 10

Oh, okay, Thank you so much. That makes since. Can you help me find two point for y=x^2/4

Answer 11

where would i plug in a number?

Answer 12

for that one you can choose any x-value...

Answer 13

So say i chose 4, it would be:
4^2/4 so, 16/4 = 4

Answer 14

yeah choose x= some number and plug into
\[y=\frac{x^2}{4} \rightarrow \text{(some number)}^2/4=\text{some other number}\]
and you will find \[(\text{some number} , \text{some other number})\]

Answer 15

so that corresponds to the point (...,...)

Answer 16

So (4,4) is a point?

Answer 17

correct!

Answer 18

& then (6,9) is a point?

Answer 19

y=6^2/4
36/4=9
(6,9)

Answer 20

yes