Question

evaluate each polynomial for x=3 and x=-3
\[4x ^{2}-6x+9\]

Answer 1

Simply plug in x = 3, and x = -3 into the equations, and then do the math.

Answer 2

i did am not sure if i did the whole thing right

Answer 3

what did you get?

Answer 4

4*(3)^2 - 6*3 + 9 =

Answer 5

but how did you get three i thought it was 4(2)^2-6(2)+9

Answer 6

i see i put 2 instead of 3

Answer 7

you're letting x=3 so wherever there's an x, replace it with a 3...

Answer 8

so would it b 12^2-12+9

Answer 9

no, do the exponentiation first 3^2... then multiply by 4

Answer 10

awww cute baby...

Answer 11

thank you and sorry but am still not getting it am a little off when it come to math

Answer 12

4x^2-6x+9
(a) x=3
4*(3)^2-6*3+9= 4*9-18+9=36-9=27
(b) x=-3
4*(-3)^2-6*(-3)+9=4*9+18+18=36+36=72
Putting x=3 and x=-3 is not giving 0 , hence they are not the roots of this equation.

Answer 13

there's this thing called order of operations... exponentiation needs to be done before multiplication. so 3^2 is done first: 3^2 = 9
so your now doing this:
4*9 - 6*3 + 9

Answer 14

ok, you got the answers..

Answer 15

are you talking to me ? @ dpalnc

Answer 16

nope, the asker...

Answer 17

thank you guys had a couple question i didnt understand.

Answer 18

ooopss , sorry ! :p