A mass is oscillating on a spring with a period of 1.20 s. At t = 0 the mass has zero speed and is at x = 4.85 cm. What is the magnitude of the acceleration at t = 3.30 s?

Question

mos1635 · Answer

V=0 =>X=Xmax=maggnute=A=4.85^-2 m
T=1.2 sec
ω=2π/Τ

α=-ω^2 * Α sin(ω t + π/2)
 go for it

anonymous · Answer

does this stand for the acceleration am trying to find α?

anonymous · Answer

am getting (-4.780cm/s^2) though not sure,i have one trial left

anonymous · Answer

u there?

mos1635 · Answer

yes

anonymous · Answer

is this α my acceleration?

anonymous · Answer

i too $$w=2\pi f$$

anonymous · Answer

and A=4.85^-2 m

anonymous · Answer

α=-ω^2 * Α sin(ω t + π/2) 
this is my amplitude A=4.85^-2 m ?
and this is my $$w=2\pi f$$
and my acceleration is this α?

mos1635 · Answer

yes

mos1635 · Answer

a=4.781906 m!!!!/sec^2
that is my ans

anonymous · Answer

meaning i should x=4.85cm to meters?

mos1635 · Answer

I am used to SI

anonymous · Answer

ok so the acceleration uis the negative of the answer u just wrote,-4.781?

mos1635 · Answer

i suppose if given x to cm
acceleretion will be acceptable to -478.1906 cm/sec^2
(yes minus)

anonymous · Answer

oops! the system says it was wrong,and dat was my last trial :)

mos1635 · Answer

you did nt put the whole value?
-478.20 should be our ans according to given values
i wrote the accurate number as i am used to (sorry)