Write an exponential function y=ab^x for a graph that includes (1,15) and (0,6). a. y=6(2.5)^x b.y=3(5)^x c.y=2.5(6)^x d.y=5(3)^x
\[y=a b ^x\] Use the points given to find a and b So we have two equations: \[15=ab^1 \text{ and } 6=ab^0\]
\[=>15=ab \text{ and } 6=a(1) \text{ since } b^0=1 \text{ assuming } b \neq 0\]
So if a=6 then what is b?
And actually you don't really need to know what b equals unless all of the answer choices are wrong lol
@myininaya \geq \[\geq\] \leq \[\leq\] \Longrightarrow \[\Longrightarrow\] sorry to interrupt O_O
so it wud be a?
@CabDel do you know it is a or do you still have doubts it is a?
Well since u said A=6 im assuming thats the first number im sure it is.
and @kreshnik what is all of that for? What does it have to do with this question? I'm sorry
Do you understand how I got a=6?
Yes kind of.
I used the ordered pairs given: \[(x_1,=1,y_1=15) \text{ and } (x_2=0,y_2=6)\] And we have that we know the equation has this form: \[y=ab^x\]
\[15=ab^1 \text{ and } 6=ab^0\]
I just replaced x with 1 and y with 15 for first ordered pair then I replaced x with 0 and y with 6 for the second ordered pair So I had two equations which I just wrote
\[15=ab \text{ and } 6=a\]
\[b^0=1 \text{ since } b \neq 0\]
=> 15=6b => 15/6=b 15/6 can be written as 2.5 because it is 2.5 lol But yes the answer is a but i just want you to be convinced that it is also a
Ok thanks im still trying to get used to this chapter its somewhat tough.
You can do it! OpenStudy is here to help and root for ya!
Yeah hah thanks!. Anyway i gtg thanks for the help
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