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Write the expression as a single natural log 3 In a-1/2(In b+In c^2) a.In 3a/0.5bc^2 b.3/2 In a/bc^2 c.In a^3/bc d.In a^3/c square root b
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d
Can u explain how u got that plz
ok we use laws of logs 3 ln a = ln a^3 ( using a ln b = ln b^a) the second part is subtracted so it will be in the denominator ( ln a - ln b = ln (1/b) ln b + ln c^2 = ln bc^2 ( using ln a + ln b = ln ab) also we have 1/2( ln bc^2) = ln (bc^2)^ (1/2) = ln c sqrtb) so we get ln a^3 - ln c sqrtb = ln a^3 / c sqrtb
Ok thanks. MAkes sense.
typo in 4th line - it should be (a/b)
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good
\[3\ln(a)−1/2(\ln(b)+\ln(c^2))=\ln(a^3)−\ln(b ^{\frac{1}{2}})-\ln(c) =\ln(\frac{a^3}{b ^{\frac{1}{2}}c})\]
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