Question

f(x)=2x/x+3. Find f^-1(x)

Answer 1

\[f(x)=\frac{2x}{x+3}\]
ley y=2x/(x+3)

\[y=\frac{2x}{x+3}\]
\[y(x+3)=2x\]
\[xy+3y=2x\]
\[xy-2x=-3y\]
\[x(y-2)=-3y\]
\[x=\frac{-3y}{y-2}\]
\[f^{-1}(x)=\frac{-3y}{y-2}\]

Answer 2

thank you)

Answer 3

but you forgot to write it like f(x)^-1=-3x/x-2

Answer 4

yeah you should correct that