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OpenStudy (anonymous):
JUST SET UP INTEGRAL: Use spherical coordinates to find the volume of the solid that lies above the cone (Phi)=3 and below the sphere Rho = 4cos(Phi) . Dont solve just how do i find the limits to integrate on?
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OpenStudy (anonymous):
Is Rho some sort of variable or number like phi that I'm unfamiliar with?
OpenStudy (turingtest):
it's the radius in spherical coordinates
OpenStudy (anonymous):
oo i see yes, your right. bc i just graphed it!
OpenStudy (turingtest):
the thing is, \[\rho=\cos(\phi)\]is not a sphere, as you noticed I'm sure
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