JUST SET UP INTEGRAL: Use spherical coordinates to find the volume of the solid that lies above
the cone (Phi)=3 and below the sphere Rho = 4cos(Phi) . Dont solve just how do i find the limits to integrate on?

Question

JUST SET UP INTEGRAL: Use spherical coordinates to find the volume of the solid that lies above
the cone  (Phi)=3 and below the sphere Rho = 4cos(Phi) . Dont solve just how do i find the limits to integrate on?

anonymous · Answer

Is Rho some sort of variable or number like phi that I'm unfamiliar with?

turingtest · Answer

it's the radius in spherical coordinates

anonymous · Answer

oo i see yes, your right. bc i just graphed it!

turingtest · Answer

the thing is, $$\rho=\cos(\phi)$$is not a sphere, as you noticed I'm sure