Question

integral of (sinx)/(1-sin^2x) dx

Answer 1

use the trig identity sin^2 + cos^2 = 1

then you are integrating sin(x)/cos^2(x) = tan(x)sec(x)

Answer 2

yes then
\[\text{substitute }u=\sec (x)\text{ and }d u=\tan (x) \sec (x)d x\]
\[\text{}=\int\limits 1 \, du\]
\[=u+c\]
\[\begin{array}{l} \text{Substitute back for }u=\sec (x): \\ \text{}=\sec (x)+\text{c} \\\end{array}\]

Answer 3

thamks